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The Planetary System, Part 2
written by Frank Hoogerbeets

April 10, 2006

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In the previous part I explained the structure of our planetary system, where the “cogs of the clock” are. In this part I’ll explain the orbital velocity of the planets, how the velocity of the cogs are related to each other. Contrary to what one would think, it is surprisingly simple to calculate the mean orbital velocity of a planet. Just as with the distances, the orbital velocities are mathematical. And as we shall see, number 15 holds the key.

But first I’ll discuss the question marks in the table shown in the first part, where according to the mathematical model one would expect planets, i.e. at the 1st, 6th and 12th position. I’ll start with the first.

In 1859 the French astronomer Urbain Jean Joseph Leverrier suspected an unknown planet between Mercury and the Sun to be responsible for the deviation in the orbit of Mercury. Leverrier also discovered Neptune 13 years earlier which was responsible for the deviation in the orbit of Uranus. For this hypothetical planet between Mercury and the Sun, he had already come up with the name Vulcan, the Roman God of fire and forgery, because of its close distance to the Sun. The planet was never found and later the deviation in the orbit of Mercury was explained using Einstein’s Relativity Theory.

Yet, according to the mathematical sequence there should be a planet at approximately 15 million kilometers from the Sun. And since number 15 appears to actually define all mathematical aspects of the planetary orbits, i.e. distance, velocity and revolution, I believe that Vulcan is either too small to observe, or not visible from the third dimension. But energetically, the orbit exists! Thus I will use the name Vulcan to refer to this orbit.

Regarding the discovery of new planets, it is interesting to observe the colective consciousness of humanity. With every newly discovered planet there was a shift in human consciousness, which resulted in new discoveries, new insights and inventions. For example, the discovery of Pluto in 1930, marked the age of plutonium or the atomic age. The “discovery” of Vulcan I believe happened subconsciously in the 1960’s marking the dawn of the computer age. Notice how in the television series Star Trek the Vulcans are being associated with logic and a keen and analytical mind, qualities also associaled with programming and using computers. Likewise the discovery of 2003-UB313 implicates that we are again at the dawn of a new era.

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asteroidengordel tussen Mars en Jupiter

The second question mark regards the position of a planet between Mars and Jupiter at approximately 420 million kilometers. There are quite some stories going around, but one in particular I find most plausible. It is about a planet called Maldek that through the fault of a humanoid species that lived there, had exploded. It is interesting to know that scientists have found that somewhere in the past many asteroids in the asteroid belt between Mars and Jupiter appear to have been exposed to very high levels of nuclear radiation. At present we have a situation on Earth where the planet is also threatened to be destroyed by nuclear power. See the parallel? Whether or not you’ll find this scenario plausible is an individual matter. Nevertheless I will refer to this planetary orbit as Maldek.

The final question mark points at a planetary orbit at approximately 23100 million kilometers. This number 23100 has something magical but of course I’m not sure if there is a planet out there at that distance. If there is it will probably take a while before it is discovered. It is dark out there and the planet would revolve at such a disctance that it would hardly reflect sunlight. Very sensitive equipment would be required to find this planet!

For those not familiar with Mathematics or Physics the following part might not be so interesting. Through some simple steps I’ll explain how the formula for the mean orbital velocity of a planet is derived. You can easily skip this part if you like and jump to the actual velocity calculation. I explain how the formula is derived because it prefectly shows that there are only relationships in the Universe and that time and space are relative and mouldable concepts.

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velocity and acceleration: v:a = r:v

From your Physics lessons you may recall the formulas for velocity and acceleration. These are:

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where v = velocity, S = distance, t = time, a = acceleration and r = radius. Of these variables there is one we can not physically observe, time. We can see velocity and acceleration when an object moves from one point to the next. We can see distance as the space between two points. But we can not see time. Therefore I’ll define time as 1 (t = 1). In that case formula A can be rewritten as:

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For any object that revolves around a central point, like a planet around the Sun, the distance it travels is the circumference that is calculated by 2πr. The equation would then be:

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Keep in mind that this equation only applies to the first of a series of objects revolving around a central point, in our case the first planet. Because there are no other objects to relate to, we would be free to set the revolution of the first object to anything we like, therefore we logically define t = 1. Consequently the mean velocity is equal to the circumference.

Every subsequent object has a lower – decelerated – mean orbital velocity in comparison to the first object. To determine the amount of deceleration, we need formula B. Through substitution we can rewrite formula B as:

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The mean orbital velocity of each subsequent object n relates to the mean orbital velocity of the first object:

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Now we apply this formula to our planetary system where according to our mathematical model the distance of the first planet to the Sun is 15 (million kilometers):

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We can determine the mean orbital velocity of every subsequent planet by entering its distance to the Sun, or radius r. In the formula 4π2153 is a constant with value 133239.6594 exactly. The result for each planet is shown in the table below. Please compare the mathematical velocity (Math.V) to the astronomically measured mean velocity (Astr.V):

Planet Math.
Mean
Distance
Calc.
Mean
Distance
Math.
Orbital
Velocity
Calc.
Orbital
Velocity
Vulcan
15
?
94,25
-
Mercury
60
57,9
47,12
47,87
Venus
105
108,2
35,62
35,02
Earth
150
149,6
29,80
29,78
Mars
240
227,9
23,56
24,13
Asteroids
(Maldek
)
420
?
17,81
-
Jupiter
780
778,4
13,07
13,06
Saturn
1500
1426,7
9,42
9,64
Uranus
2940
2871,0
6,73
6,79
Neptune
4380
4498,3
5,52
5,43
Pluto
5820
5906,3
4,78
4,74
Eris
11580
10142
3,39
3,44
?
23100
?
2,40
-

The table shows how close the observed values are to the mathematical values. We should not be surprised by this, but we could wonder why we do not learn this knowledge in school or at universities!

If you understand how the above formula is derived, you can see that the values found for the mean orbital velocities only exist in realtionship to the first planet. In the next and final part I’ll discuss the mean orbital time or revolution of the planets. It will again demonstrate how relative time and space actually are.

Copyright © Frank Hoogerbeets, Ditrianum Media Center You have my permission to copy and distribute this article as long as you do not change its content including this copyright notice.

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